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A goldsmith has two alloys of gold, the first being 70% pure and the second being 60% pure. How many ounces of the 60% pure gold must be used to make 100 ounces of an alloy which will be 66% gold?
in Math by engr III (10.4k points) | 124 views

1 Answer

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70% = 100-x

60% = x

66% = 100

0.70(100-x) + 0.60(x) = 0.66(100)

70 - 0.7x + 0.6x = 66

x = 40 oz.

by cadet engr (310 points)

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