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On a certain trip, Edgar drives 231 km in exactly the same time as Edwin drive 308 km. If Erwin’s rate exceeded that of Edgar by 13 kph, determine the rate of Erwin.
in Math by engr III (10.4k points) | 32 views

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Let: v = rated of Erwin

 v -13 = rate of Edgar

t1 = t2

231 / v-13 = 308 / v

231v = 308v - 4004

v = 52 kph

by cadet engr (310 points)
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